Solving Linear Equation
Equation :
(1) a mathematical expression containing the symbol "="
L.H.S = R.H.S
(2) often contains ALGEBRA => variables, such as x and y (to represent the number that we do not know)
(3) examples: y = 3, y + 3 = 10, y = 2x + 3
(4) solving an equation => finding the value of the variable/s (unknown).
(5) must follow the order of operations - BIDMAS ( Bracket, Indices, Divide, Multiply, Add, Subtract).
Example
Solve for x
5x + 7 = 2x + 28
Step 1 : "move" the variable to LHS, and numbers to RHS
LHS RHS
5x + 7 = 2x + 28
5x -2x + 7 - 7 = 2x + 28 - 2x - 7
5x -2x + 7 - 7 = 2x + 28 - 2x - 7
[ when "moving", the equation must remain 'balance", thus -2x and -7 are applied to both side]
Step2 : Do x/+- to solve
5x – 2x = 28 – 7
3x = 21
x = 7
["Move" also => "changing" the sign of the number/variable at the other side (LHS/RHS).]
Example
Solve for 2y + 4 = y -6
2y + 4 -y - 4 = y - 6 - y - 4 (step 1: move y to LHS, nos to RHS)
2y + 4 -y - 4 = y - 6 - y - 4
y = -10
Solving Fractional Equations (Linear equation)
Linear fractional Equation can usually be solved by simplifying the equation to having a single denominator.
Example
Solve y/2 + y/3 = 2
Step 1 : Find the lowest common factor (LCM) for the denominators
LCM of 2 and 3 = 6
Step 2 : Combine into single fraction
½y + ⅓y = 2
3 x y + 2 x y = 2
3 x 2 2 x 3
3y + 2y = 2
6
6 x 5y = 2 x 6 (multiply 6 => "1/6(LHS) = x 6 (RHS))
6
5y = 12
y = 12/5 = 2 2/5
Example
Solve y + y – 2 = 3
3 4
LCM of 3 and 4 = 12
4x y + 3x (y – 2) = 3 (Step 1 :Find LCM and multiply)
4x 3 3x 4
4y + 3y – 6 = 3 (Step2 : Combine into single fraction)
12
7x – 6 = 3 (Step3: Cross-over the denominator and solve)
12
7x – 6 = 3 x 12
7x = 36 + 6
x = 42/7 = 6
Example
Solve 3 = 3
x – 2
3 = 3(x – 2) (Step1: Bring the denominator to the right)
3 = 3x – 6 (Step2: Expand the bracket)
3x – 6 = 3 (Step3: Solve for x)
3x = 3 + 6
x = 9/3
= 3
No comments:
Post a Comment
Note: only a member of this blog may post a comment.