Pythagoras' Theorem
For a right angle triangle:-
If the hypotenuse has length c, and the sides have lengths a and b, then
c2 = a2 + b2
[hypotenuse = the length across or opposite the right angle / longest length]
=> if the sides of a triangle have lengths a, b and c, such that c2 = a2 + b2,
then the triangle is a right-angle triangle.
What is c?
Using c2 = a2 + b2
52 + 122
= 25 + 144
= √169
= 13
Example
If every square is 1 unit, what is a?
Using c2 = a2 + b2
25 = 52, 9 = 32
52 = a2 + 32
a2 = 25 - 9
a2 = √16
a = 4
Trigonometric Ratios
Tangent ,Cosine and Sine
To find angle x or any of the sides, we can use
Tan x = Opposite = b TOA
Adjacent a
Cos x = Adjacent = a CAH
Hypotenuse c
Sin x = Opposite = b SOH
Hypotenuse c
Example
(b) Sin X
(c) Cos X
(d) Tan X
(e) Angle X
a. Length AC
c2 = a2 + b2 Step 1 : which formula to use? Label a=6, b = 8
[Right angle ◺, use Pythagoras Theorem]
c2 = 62 + 82 Step 2 : Compute and answer
c = √36 + 64
= 10
AC = 10 cm
b. Sin X = Opp/Hyp Step 1 : Determine the formula and label
= 6/10 Step 2 : Compute and answer
= 3/5
c. Cos X = Adj/Hyp Step 1 : Determine the formula and label
= 8/10 Step 2 : Compute and answer
= 4/5
d. Tan X = Opp/Adj
= 6/8 = 3/4
e. Tqn X = 6/8 Step 1 : Determine the formula and label
X = Tan-1(6/8) Step 2 : Compute and answer
= 36.86o
[If possible, always use the value given to do the computation instead of a computed value. This is to avoid wrong answer in case there is of a mistake in the computed value]
Sine Rule
a = b = c
SinA SinB SinC
or
SinA = SinB = SinC
a b c
a2 = b2 + c2 – 2bcCosA
Note:
1. The value of Sinθ and Cosθ is between -1 to 1 =>
-1 ≤ Sinθ ≤ 1
-1 ≤ Sinθ ≤ 1
Check your computation if your answer for Sinθ orCosθ is not within -1 to 1
2. For Pythagoras Theorem, the Hypotenuse length is the longest
=> the value of both sides are smaller than the hypotenuse length.
Check your computation if any side has a bigger value than the hypotenuse.
3. If possible, always use the given values in the question for computation.
Find
(a) length BC
(b) Sin Y
(c) Cos Y
(d) Tan Y
(e) Angle Y
(f) Sin Z
(g) Cos Z
(h) Tan Z
(i) Angle Z
Answer
a. AC2 = AB2 + BC2 Step 1 : Right Angle ◺, use Pythagoras T]
132 = 52 + BC2 Step 2 : Label Diagram and Compute
BC2 = 132 - 52
BC = √169 - 25
= √144
= 12
b. Sin Y = O/H Step 1 : Determine the formula and labe
= 12 / 13 Step 2 : Label Diagram and Compute
c. Cos Y = A/H
= 5/13
d. Tan Y = O/A
= 12/5
e. Y = Cos -1 (5/13)
= 67.38o
f. Sin Z = 12/13
g. Cos Z = 5/13
h. Tan Z = 5/12
i. Angle Z = 180 - 90 - 67.38o
= 22.62o
[If possible, always use the given values in the question; this is to avoid subsequent wrong answers if there is error in a computed value.]
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