Showing posts with label GCE NA level Maths. Show all posts
Showing posts with label GCE NA level Maths. Show all posts

Monday, 23 March 2020

S3TN Solving Fractional Equations and Others

Solving Fractional Quadratic Equations


Cross-Multiplying =>

            a = c     =>      x ba  =   c   x bd    =>   ad = bc

            b    d                        b       d


[[ The Equation must be ax2+ bx + c = 0 before factorising ]]


Example 

solve    6   = x + 3

          x + 4


            6      =    x + 3 

         x + 4

 6 = (x + 3)(x + 4)         (Step1:  Cross-Multiply)



   6 = x2+ 7x + 12          (Step2: Expand to form a quadratic equation)

   x2+ 7x + 12 – 6 = 0

   x2+ 7x  + 6 = 0

  (x + 1)(x + 6) = 0         (Step3: Factorise and Solve for x)

   x + 1 = 0 or x + 6 = 0

   x = -1 or x = -6


Example

Solve      1       +    2       = 5

            x -2        x – 3 


              (x – 3)  + 2 x (x – 2)   = 5        (Step1: LCM the denominator)

        (x - 3)(x -2)  (x – 2)(x – 3)

            x – 3  + 2x – 4  =  5                   (Step 2 : Combine to single fraction)

              (x – 2)(x -3)

         x + 2x – 3 – 4 = 5        

           (x – 2)(x -3)

               3x – 7       = 5

         (x – 2)(x – 3)


          3x – 7 = 5(x – 2)(x – 3).              (Step 3 : Cross-Multiply and Expand)

          3x – 7 = 5(x2– 5x + 6)

          3x – 7 = 5x2– 5x + 6

          5x2– 5x + 6 – 3x + 7 = 0. 

          5x2-8x + 13 = 0                           (Step 4: Factorise and Solve for x)                                       

          (5x + 13)(x + 1) = 0                                           5x   \ /    13

     5x + 13 = 0 or x + 1 = 0                                           x    / \     1  

           x = -13/5 or x = -1


Solving Equations by equating Coefficients


Example


Find the value of A, B and C

2x4 - 13x3 + 19x2 + 5x + 1 = (x - 4)(Ax + 1)(x2 + Bx + 1) + C


Tips : 
1. Such questions are usually solved by equating the coefficient values
2. If there are more than 2 brackets, expands in pairs
3. Solve the unit value first, and then the highest powers of X


Step 1 - Expand brackets (if needed)

   2x4 - 13x3 + 19x2 + 5x + 1 = (x - 4)(Ax + 1)(x2 + Bx + 1) + C

   2x4 - 13x3 + 19x2 + 5x + 1 = (x - 4)(Ax + 1)(x2 + Bx + 1) + C [Expands 1 pair]


                    (x - 4) (Ax + 1) = (Ax2 + (1 - 4)x - 4) (x2 + Bx + 1) + C


  2x4 - 13x3 + 19x2 + 5x + 1 = (Ax2 + (1 - 4A)x - 4)(x2 + Bx + 1) + C


Step 2 - extract  and solve from comparing coefficients 

  Extract coefficient  of x4.   [=> x2 x x2 , x3 x x , x4 x unit value ]


      2x4 - 13x3 + 19x2 + 5x + 1 = (Ax2 + (1 - 4A)x - 4)(x2 + Bx + 1) + C

                   2x4  =  Ax2 x x2

    A = 2  [Equating x4 coefficient]

    

  Extract and equating coefficient of unit value

    1 = (-4 x 1) + C

C = 1 + 4

C = 5


Step 3 - Substitute values and find remaining unknown


     2x4 - 13x3 + 19x2 + 5x + 1 = (2x2 -7x - 4)(x2 + Bx + 1) + 5


  Extract and equating x coefficients

5x = -7x x 1 - 4Bx

             5 = -7 - 4B

  4B = -12

                B = -3 


A = 2, B = -3, C = 5



Monday, 20 January 2020

N2-G123 Ratios

Ratio compares two or more quantities.


            Symbol of ratio is    


Ratio of quantity A to quantity B s written as     

                  A : B                                                    

** Ratio has no unit of measure


Example

Write the ratio 200:  250 in its simplest form

                  200 : 250

                  20÷5 : 25 ÷ 5

                      4 : 5

                  

                  a : b: c => a: b , b : c


Equivalent Ratios

Example

                       4 : 10 

                = 4 ÷2 : 10÷2

                =     2 : 5

4 : 10 and 2 : 5 are equivalent ratios.


Ratio in its simplest form

Example

Write 8 : 12: 36 in its simplest form


Step: Find the common factors for the given numbers and reduce

            8 ÷4 : 12÷4 : 36÷4

            2 : 3 : 9

       

Example: Write the ratio 200:  250 in its simplest form

                    200 : 250

                  20÷5 : 25 ÷ 5

                        4 : 5


Example

The ratio of the number of tables to the number of chairs is 1 : 4 in the restaurant. There are 6 tables, how many chairs are there?


Step 1 : Write the ratio and number of tables

T  C

1 : 4

Step 2 : Write the number of tables on both side of the ratio and multiply

T   C

1  : 4

                    x 4   x4

= 4  : 16


Step3 : Answer 

There are 16 chairs


Ratio with different Unit of Measure (UOM)

The UOM must be the same when comparing two of more quantities


Example:

John has $1 and Sally has 80cts as their daily allowance. What is the ratio of their allowance?


Step 1 : Convert the amount to the same unit (of the 'smaller' UOM)

$1 = 100cts

Step 2 :  Write the ratio and reduce the the lowest term

100 : 80

5  10 : 8 4

      5 : 4


Step 3 : Write the Answer

The ration is 5 : 4


Ratio involving Fractions and Decimals

Example

Express the following ratios in its simplest form.

  1.2 : 3 


Step 1 : Multiply 10 to both side (to remove the decimal)

x10.  1.2. :   3 x 10

12 :  30

Step 2 : Reduce the simplest term


<< divide by 6 for both side >>

    2    1230     5        

The ratio is 2 :  5


Example

Express the following ratios in its simplest form.


b.         1 ¾.  :    2 ½    


Step 1: Change both to improper fractions

    7  :  5

             4     2


Step 2 :  Make both side to have the same denominator

<< multiply 2 , by 2 >>

    7  :  x 2

             4     2  x 2


    7  :  10  

             4      4 

Step 3 : Write the numerators as the ratio

7 : 10


Connecting Ratio with Fraction

For a ratio   A : B, the 'total number of parts' = A + B


Thus in fraction form,    A's part is A / A+B

              B's part is B / A+B 

Example

There are 10 girls and 15 boys.

The ratio of the number of girls to the number of boys = 

10 : 15    or    2   :   3

The total part = 2 + 3 = 5


=>  Number of girls = 2/3 of number of boys

=>  Number of girls = 2/5 of the total

=>  Number of boys = 3/2 of number of girls

=>  Number of boys = 3/5 of the total.


Example

Abby and Bobby have 10 oranges altogether. 

The oranges are to be divided in the ratio of 3 : 2

How many oranges will each of them get?


Step 1: Find the total parts 

Total = 3 + 2 = 5


Step 2 : Compute their fraction's

  Abby = 3/5 , Bobby = 2/5


Step 3 : Compute by multiplying total quantity with the fractions

Abby has 3/5 x 10 = 6 oranges

Bobby has 2/5 x 10 = 4 oranges


Practice

1.  Express the following ratios in its simplest form.

(a) 4 :  20 [1 : 5]

(b) 35 : 14 [7 : 2] 

(c)    64 : 56 : 16 [8 : 7 : 2] 


2.   Express the following ratios in its simplest form.

a.    kg :  2 kg                        [5 : 12 ]

b.  1.6 cm : 4 mm                     [4 : 1 ]

c.  1 ½ hr : 20 mins                  [9 : 2 ]

d.  250 ml : 1 litre                     [1 : 4 ]


3.  Mary and Andy share a pizza in the ratio of 1 : 2. Andy gets 4 slices of the pizza. How many slices does Mary get? [2]


4.  Alice, Betty and Coby share their marbles in the ratio of 2 : 3 : 5. Find the amount each gets for each of the marbles.

a.  420 (b) 70                   [a. 84, 126, 210     b. 14, 21, 35]