Wednesday, 10 January 2018

R3 Ratio : Two set of Ratios and 3 Objects


Ratios

TWO SETS OF RATIOS AND 3 OBJECTS/ITEMS
One type of question has 2 sets of ratios and 3 items/objects. One of the objects is the common item in the 2 sets of ratio.  
Solve the question by using common item to ‘link’ the two sets of ratio. 
Example
The ratio of the number of oranges to apples is 2:5 and the ratio of the number of oranges to pears is 6:7. What is the ratio of the number of orange to apples to pears?
Method
Step1: Write the sets of ratio side by side
     O         A                                 O         P
     2          5                                  6          7

Step2: Identify common item (Orange)?
            Put the common item of the ratio in the middle
A         O
            5          2          
                        O         P
                        6          7
Step3: Find/Draw Common Multiple in-line and ‘equal’ the common item value
            (Common multiple for 2 and 6 is 6)

A         O
            5x 3      2x 3
                        O         P
                        6          7
            
A         O         P
            15       6          7

Step4: Solve question to the sequence required
            (It is orange to apples to pears.)

      The ratio of the number of orange to apples to pears is 6:15:7 

Note: The sequence of the ratios relative to the items must be maintained.

Example
Ali and Billy had a number of marbles in the ratio of 2:7. Ali and Cecil had a number of marbles in the ratio of 3:1. It they had a total of 168 marbles altogether, how many more marbles did Billy have than Cecil?
Method
Step1: Write the sets of Ratio side by side
A         B                                 A         C
2          7                                  3          1

Step2: Who is common, Ali)?
            Draw/Put the common item of the ratio in the middle
B         A
            7          2          
                        A         C
                        3          1
Step3: Find the common multiple and equal the common item value
            (Common multiple for 2 and 3 is 6)
B         A
            7x3       2x3       
                        A         C
                        3x2       1x2
Step4:  Solve question to the sequence required
B         A
            21       6          
                        A         C
                        6          2
B         A         C
      21       6          2

      Total = 21 + 6 + 2 = 28u
      28 u = 168, u = 6
      Cecil has 2 x 6 = 12 cards, Billy has 21 x 6 = 126 cards
            Billy has 126 – 12 = 114 cards more than Cecil.

Wednesday, 29 June 2016

The Mathbooklets

This blog aims to share/provide the basic concept/definition, a step-by-step method to solve math questions for each topic. Hopefully, more learners can understand and enjoy mathematics, and educators have another way to explain and help their students.

The content is created based on my knowledge and understanding of mathematics concepts and developing methods to use it. The methods may not apply to all type of questions. If in doubt, please ask the professional. It is not 100% accurate or correct.


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