Wednesday 10 January 2018

R3 Ratio : Two set of Ratios and 3 Objects


Ratios

TWO SETS OF RATIOS AND 3 OBJECTS/ITEMS
One type of question has 2 sets of ratios and 3 items/objects. One of the objects is the common item in the 2 sets of ratio.  
Solve the question by using common item to ‘link’ the two sets of ratio. 
Example
The ratio of the number of oranges to apples is 2:5 and the ratio of the number of oranges to pears is 6:7. What is the ratio of the number of orange to apples to pears?
Method
Step1: Write the sets of ratio side by side
     O         A                                 O         P
     2          5                                  6          7

Step2: Identify common item (Orange)?
            Put the common item of the ratio in the middle
A         O
            5          2          
                        O         P
                        6          7
Step3: Find/Draw Common Multiple in-line and ‘equal’ the common item value
            (Common multiple for 2 and 6 is 6)

A         O
            5x 3      2x 3
                        O         P
                        6          7
            
A         O         P
            15       6          7

Step4: Solve question to the sequence required
            (It is orange to apples to pears.)

      The ratio of the number of orange to apples to pears is 6:15:7 

Note: The sequence of the ratios relative to the items must be maintained.

Example
Ali and Billy had a number of marbles in the ratio of 2:7. Ali and Cecil had a number of marbles in the ratio of 3:1. It they had a total of 168 marbles altogether, how many more marbles did Billy have than Cecil?
Method
Step1: Write the sets of Ratio side by side
A         B                                 A         C
2          7                                  3          1

Step2: Who is common, Ali)?
            Draw/Put the common item of the ratio in the middle
B         A
            7          2          
                        A         C
                        3          1
Step3: Find the common multiple and equal the common item value
            (Common multiple for 2 and 3 is 6)
B         A
            7x3       2x3       
                        A         C
                        3x2       1x2
Step4:  Solve question to the sequence required
B         A
            21       6          
                        A         C
                        6          2
B         A         C
      21       6          2

      Total = 21 + 6 + 2 = 28u
      28 u = 168, u = 6
      Cecil has 2 x 6 = 12 cards, Billy has 21 x 6 = 126 cards
            Billy has 126 – 12 = 114 cards more than Cecil.